Given an array of integers, calculate the ratios of its elements that are positive, negative, and zero. Print the decimal value of each fraction on a new line with **6** places after the decimal.

**Note:** This challenge introduces precision problems. The test cases are scaled to **six decimal places**, though answers with an absolute error of up to 10^4 are acceptable.

**Example**

arr = [1, 1, 0, -1, -1]

There are **n= 5** elements, two positive, two negative, and one zero. Their ratios are (2/5) = 0.400000 , (2/5) = 0.400000 and (1/5) = 0.200000. Results are printed as each in new lines:**0.4000000.4000000.200000**

Coding language => **Python**

Coding logic => **own logic**

**Solutions**:

arr = [-4, 3, -9, 0, 4, 1] # iterating each number in list def findcount(numbers): pos_count, neg_count, zero_count = 0, 0, 0 for num in numbers: # checking condition if num > 0: pos_count += 1 elif num == 0: zero_count += 1 elif num < 0: neg_count += 1 return [pos_count, neg_count, zero_count] def plusMinus(arr): l = len(arr) ratiolist = findcount(arr) ratioOfPositive = ratiolist[0] / l ratioOfNegative = ratiolist[1] / l ratioOfZero = ratiolist[2] / l print(format(ratioOfPositive,'.6f' )+"\n"+ format(ratioOfNegative,'.6f' )+"\n"+ format(ratioOfZero,'.6f' )) plusMinus(arr)

OUTPUT:**0.4000000.4000000.200000**

**NOTE:** python print float digit with 6 decimal point

=> format(‘2′,’.6f’)

=> 2.000000