Given an array of integers, calculate the ratios of its elements that are positive, negative, and zero. Print the decimal value of each fraction on a new line with 6 places after the decimal.

Note: This challenge introduces precision problems. The test cases are scaled to six decimal places, though answers with an absolute error of up to 10^4 are acceptable.

Example
arr = [1, 1, 0, -1, -1]
There are n= 5 elements, two positive, two negative, and one zero. Their ratios are (2/5) = 0.400000 , (2/5) = 0.400000 and (1/5) = 0.200000. Results are printed as each in new lines:
0.400000
0.400000
0.200000

Coding language => Python
Coding logic => own logic

Solutions:

arr = [-4, 3, -9, 0, 4, 1]

 
# iterating each number in list
def findcount(numbers):
    pos_count, neg_count, zero_count = 0, 0, 0
    for num in numbers:
        # checking condition
        if num > 0:
            pos_count += 1
        elif num == 0:
            zero_count += 1
        elif num < 0:
            neg_count += 1
    return [pos_count, neg_count, zero_count]

def plusMinus(arr):
    l = len(arr)
    ratiolist = findcount(arr) 
    ratioOfPositive = ratiolist[0] / l
    ratioOfNegative = ratiolist[1] / l
    ratioOfZero = ratiolist[2] / l
    print(format(ratioOfPositive,'.6f' )+"\n"+ format(ratioOfNegative,'.6f' )+"\n"+ format(ratioOfZero,'.6f' ))

plusMinus(arr)

OUTPUT:
0.400000
0.400000
0.200000

NOTE: python print float digit with 6 decimal point
=> format(‘2′,’.6f’)
=> 2.000000