hacker-rank | min-max sum of array

find the minimum and maximum values that can be calculated by summing exactly four of the five integers. Then print the respective minimum and maximum values as a single line of two space-separated long integers.

Example:
arr = [1,3,5,7,9]

The minimum sum is 1+3+5+7 = 16 and the maximum sum is 3+5+7+9 = 24. The function prints

16 24

Output Format
Print two space-separated long integers denoting the respective minimum and maximum values that can be calculated by summing exactly four of the five integers. (The output can be greater than a 32-bit integer.)

Sample Input
1 2 3 4 5

Sample Output
10 14

Explanation:

The numbers are 1, 2, 3, 4, and 5. Calculate the following sums using four of the five integers:

  • Sum everything except 1, the sum is 1+2+3+4+5 = 14.
  • Sum everything except 2, the sum is 1+3+4+5 = 13.
  • Sum everything except 3, the sum is 1+2+4+5 = 12.
  • Sum everything except 4, the sum is 1+2+3+5 = 11.
  • Sum everything except 5, the sum is 1+2+3+4 = 10.

From the above calculation, 10 is the minimum and 14 is maximum.

Code language => Python

Solutions:

arr = [1,3,5,7,9]

def sumOfarray(arry):
    s = 0
    l = len(arry)
    for x in range(0,l):
        s =s+ arry[x]
    return s


def findminandmax(arr):
    sumOfarr = []
    for i in range(0, len(arr)):
        a  = arr[:]
        a.pop(i)
        sumOfarr.append(sumOfarray(a))
    return print(str(min(sumOfarr)) + " "+ str(max(sumOfarr)))

findminandmax(arr)

###output###
# 16 24

Note: we use a deep clone([:]) or deep copy for changing an array without affecting previous array values.

Example for deep clone:
1st case without deep clone

# Example for deep clone:
a = [5, 2]
b  =  a
b[0] = 100
print(a)
###output###
#[100 ,2]

2nd case with a deep clone [:]

# if we dont want to change variable a, then
a = [5,2]
b = a[:]
b[0] = 100
print(a)
###output###
#[5,2]

hacker-rank | print staircase right aligned with space and hash

Staircase detail

This is a staircase of size: n = 4

#
##
###
####

Note: Right-aligned #

Its base and height are both equal to n. It is drawn using # symbols and spaces. The last line is not preceded by any spaces.

Query: Write a program that prints a staircase of size n.

Function Description
The staircase has the following parameter(s):

int n: an integer
Print a staircase as described above.

Input Format
A single integer, n, denoting the size of the staircase.

Code language => Python

Solutions:

def staircase(n):
    l = n
    for x in range(0,l):
        ns = l-x -1
        print(ns * " "+("#")*(x+1))

staircase(6)

# output
     #
    ##
   ###
  ####
 #####
######

Note:
In python, we can multiply a string. eg,
=> “ab” * 2
=> abab
From above we can multiply the “ab” 2 times. So, we use the same concept to print space.

hacker-rank | calculate ratios of positive, negative, and zero elements

Given an array of integers, calculate the ratios of its elements that are positive, negative, and zero. Print the decimal value of each fraction on a new line with 6 places after the decimal.


Note: This challenge introduces precision problems. The test cases are scaled to six decimal places, though answers with an absolute error of up to 10^4 are acceptable.

Example
arr = [1, 1, 0, -1, -1]
There are n= 5 elements, two positive, two negative, and one zero. Their ratios are (2/5) = 0.400000 , (2/5) = 0.400000 and (1/5) = 0.200000. Results are printed as each in new lines:
0.400000
0.400000
0.200000

Coding language => Python
Coding logic => own logic

Solutions:

arr = [-4, 3, -9, 0, 4, 1]

 
# iterating each number in list
def findcount(numbers):
    pos_count, neg_count, zero_count = 0, 0, 0
    for num in numbers:
        # checking condition
        if num > 0:
            pos_count += 1
        elif num == 0:
            zero_count += 1
        elif num < 0:
            neg_count += 1
    return [pos_count, neg_count, zero_count]

def plusMinus(arr):
    l = len(arr)
    ratiolist = findcount(arr) 
    ratioOfPositive = ratiolist[0] / l
    ratioOfNegative = ratiolist[1] / l
    ratioOfZero = ratiolist[2] / l
    print(format(ratioOfPositive,'.6f' )+"\n"+ format(ratioOfNegative,'.6f' )+"\n"+ format(ratioOfZero,'.6f' ))

plusMinus(arr)

OUTPUT:
0.400000
0.400000
0.200000

NOTE: python print float digit with 6 decimal point
=> format(‘2′,’.6f’)
=> 2.000000

find factorial of a number in python simple way

find factorial in python easy way only 5 lines

Coding Style = my style of coding

Coding language = python

def findFactorial(num):
    a = 1
    for x in range(0, num):
       a = a * (num -x)
    return a
print(findFactorial(5))

# 5! * 4! * 3! * 2! * 1!
# output : 
# 120

Explanation:
for x in range(0, 5)
Already set a = 1, so

First loop
=> a = 1 * (5 – 0)
=> a = 5

Second loop
=> a = 5 * (5 – 1)
=> a = 5 * 4
=> a = 20

Third loop
=> a = 20 * (5 – 2)
=> a = 20 * 3
=> a = 60

Fourth loop
=> a = 60 * (5 – 3)
=> a = 60 * 2
=> a = 120

Fourth loop
=> a = 120 * (5 – 4)
=> a = 120 * 1
=> a = 120
After that x range is now 4, we set only in the range between 0 to 5
Now loop ended. So we print( findFactorial(5) ) => its return answer 120.

Hope this logic will help you to understand the factorial concept in programming. Thank you for reading!



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Regex For Regex Example Description
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`+el.regex+`
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